Imagine that you have a loaded die (that’s the singular of ‘dice’). This means the die is biased. It’s not fair. If you roll it, the probability that you’ll get a \(4\) is higher than the probability of getting any other number. You roll the die a few times and analyze the data.

Decide which of the following is more likely to happen:

\[A. \quad 2, 5, 3, 4, 6\] \[B. \quad 4, 2, 5, 3, 4, 6\]

Drop a comment below with your answer, and please *do not explain your answer* because I don’t want anyone to get influenced by other peoples’ comments. Just a simple \(A\) or a \(B\) will suffice.

I’m going to bed now and when I wake up the next day I hope to see a lot of comments! :)

Until then!

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestOption 1: A

Upvote this comment if you think it is right.

Log in to reply

Option 2: B

Upvote this comment if you think it is right.

Log in to reply

I say A.

Log in to reply

Option B

Log in to reply

Because apparently this one person's "day" meaning 15 days in real world, I decide to screw it and give my reasoning. Here, \(P(A), P(B), P(4)\) are probabilities of getting the sequence \(A\), the sequence \(B\), and the throw \(4\) in that order.

\(A\) is more likely. Note that \(P(B) = P(4) \cdot P(A) \le 1 \cdot P(A) = P(A)\), so the probability of getting \(B\) is less than or equal to \(A\).

Log in to reply

A

Log in to reply

@Mursalin Habib It has been a day!

Log in to reply

Option A

Log in to reply

B

Log in to reply

I see it's possible that both are equally likely to happen. But one option cannot be more likely than the other; it's either equally likely or less likely depending on the probability distribution.

Log in to reply

Why is that? If something is less likely to happen then something else, then that something else is more likely to happen than the first something.

Log in to reply

I mean one particular option cannot be more likely than the other one, not any one option cannot be more likely. Ambiguity; my bad.

Log in to reply

B

Log in to reply