# Test of divisibility for 7, 11 and 13

87985 is divisible by 7 or not ?

Combined test of divisibility for 7, 11 or 13.Method is useful for any big or small digit number.

Step 1 Make groups of 3 digits from the end (unit place) in above case groups are 87 985

Step 2 add all groups at odd places (1st, 3rd, 5th etc..) here only 1 group 985

Step 3 add all groups at even places (2nd, 4th, 6th, etc..) here only 1 group 87 (group may be of 1 or 2 or 3 digits depending on number of digits in given number)

Step 4 find difference in above 2 additions here 985 – 87 = 898

Step divide the difference by 7, 11, 0r 13 as the case may be.

898/7 = 128 2/7 it is not divisible 7, for test of eleven apply test not divisible by 11 and 898/13 = 69 1/3 not divisible by 13.

Even you can find remainder using this method.

2 years, 1 month ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$