The must be a faster way - 1

If p,q,rp,q,r are the roots of the equation


Prove that p=q=rp=q=r.

Elementary proof:

By Vieta's Formula,




From the third equation,


Substitute to the second equation,





Substitute pr=q2pr=q^2 into the third equation,

q3=r3    q=rq^3=r^3\implies q=r




p=r    p=q=rp=r \implies p=q=r

Can you find a better proof?

Note by Christopher Boo
6 years, 11 months ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link]( link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}


Sort by:

Top Newest

Put x=rx=r in the equation. Since rr is a root, we immediately get pr=q2pr=q^2 (assuming r0r\neq 0). Also pqr=r3pqr=r^3. The rest follows from these two.

Abhishek Sinha - 6 years, 11 months ago

Log in to reply

Brilliant proof!!!

Anuj Shikarkhane - 6 years, 11 months ago

Log in to reply

Brilliant! @Abhishek Sinha

Christopher Boo - 6 years, 11 months ago

Log in to reply

we can assume that p=q . Which means that we are assuming p to be the repeated root of the given function . Differentiate the given cubic and let it be g(x). then substitute p in g(x) Since we have assumed p to be repeated root thus it will also be the root of g(x). on substituting p in the equation we will get p=q which concurs with our assumption.

Prince Kumar Maurya - 6 years, 9 months ago

Log in to reply

Indeed, I've found a much faster solution. Using the cubic formula, we get that


is one of pp, qq, and rr. We can find the other roots by dividing out, and the rest of the proof is omitted.

Cody Johnson - 6 years, 11 months ago

Log in to reply

Honestly, why do you love to bash out all the problems so much?

Sagnik Saha - 6 years, 11 months ago

Log in to reply


Problem Loading...

Note Loading...

Set Loading...