...that is yet unsolved.

I joined almost at launch, and things were RADICALLY different back then in terms of the website's interface. One of the differences is a forums section (which was a pretty awesome feature, I don't know why anyone decided to take it down), and one of the threads contained a cool problem:

Diverges or Converges?

**\[\displaystyle \sum _{ n=0 }^{ \infty }{ \frac {(-1)^n \tau(2n+1) }{2n+1 } } ,\]**

where \(\tau(N)\) denotes the number of positive integer divisors of N.

I have the answer. I also have two solutions. However, what is missing is a proof of the answer.

This seems to be a hard-core Number Theory problem. So whoever likes these, you're more than welcome to try this problem!

I shall post the answers I have if necessary. But first, give it your own shot.

Good luck!

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## Comments

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TopNewestIt sure seems to converge to 1.5708...., which looks a lot like \( \dfrac { \pi }{ 2 } \) ...., but I have no proof. It'd be fascinating if it really is that.

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Im getting something close to \(\frac{1-\sqrt(5)}{2}\)

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The Golden Ratio? Wow! You're almost there! 0.00002% error! A hint: the expression involves \(\pi\).

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Anyway, I've been looking for this notebook I had solutions in for about an hour, and it's gone! Dunno what happened to it, but there I had lots of other cool stuff and I hope to find it someday.

When I do, I'll post it up right away.

Cheers

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Honestly, I did not expect this problem to blow up after two months. But just to line things up, no it does not converge to that. Good try though.

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Okay, better define exactly what "number of positive integer divisors of N" means, because I've numerically worked this out for n up to 200,000, and that's the number I'm getting and it looks pretty stable, i.e., very little difference between n = 100,000 and n = 200,000. Also, I'm adding the series in pairs, i.e., eliminating this alternating jigger.

For example, 13 would have 2 divisors, while 12 would have 6. Yes or no?

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Oh, and for the record: the solutions look MAD complicated! Like, alien complicated.

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I was too distracted with another problem I was working on. So, finally, I've decided to tackle a few electricity problems, and I think I'm doing all right with those. Even though I still don't like it much.

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alrighty.

LOL!!!

s

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Dam I gotta write like a Nobel-Peace Prize quality comment to get an upvote from you.

And that makes it only so much precious ;p

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\[55555555555555555555555555555555555555555555555555555555555555555555555555555!\]

(I'll bet \(5$\) that you read that as a factorial ;))

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Wait...that thread doesn't exist anymore?

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It probably does but it's really old and I forgot what was the name of the thread so... I just posted it all over.

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Do you have a link to the solutions?

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