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Please solve:

\(16^{\sin2x}+16^{\cos2x}=10\)

where

\( x\in(0,\pi)\)

Note by Krishna Jha 3 years, 10 months ago

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Comment deleted Dec 13, 2013

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I think you have taken the log in very different way. You might have missed "+" sign with "x" sign. You must check it

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TopNewestComment deleted Dec 13, 2013

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I think you have taken the log in very different way. You might have missed "+" sign with "x" sign. You must check it

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