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# Trigonometry Help

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Note by Dan Ley
8 months, 1 week ago

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Is d equal to a^2-b^2 @Dan Ley

- 8 months ago

I think you can do it by expanding the bottom, and multiplying the top out by $$d+acosc$$, and showing that these two expressions are equal. But I can't see a better, nice method.

- 8 months ago

I agree let me work on it I will get back to you after 2-3 days I am a little busy Board exams are coming up

- 8 months ago

That's fine don't stress over it, it's just part of my school project:) Good luck with the exams bro.

- 8 months ago

Thanks But I will try

- 8 months ago

No, $$d^2=a^2-b^2$$, so $$d=\sqrt{a^2-b^2}$$.

- 8 months ago

Ok

- 8 months ago

@Neel Khare don't worry about it, I just multiplied the equation out so that there were no fractions, and replaced $$\sin^2c$$ with $$1-\cos^2c$$. Then you can show that the two expressions are equal, but it's not fun or elegant or particularly difficult...

- 8 months ago

Comment deleted 7 months ago

I think the right person for this is @Neel Khare

- 8 months, 1 week ago