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Trigonometry Help


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Note by Dan Ley
8 months, 1 week ago

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Is d equal to a^2-b^2 @Dan Ley

Neel Khare - 8 months ago

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I think you can do it by expanding the bottom, and multiplying the top out by \(d+acosc\), and showing that these two expressions are equal. But I can't see a better, nice method.

Dan Ley - 8 months ago

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I agree let me work on it I will get back to you after 2-3 days I am a little busy Board exams are coming up

Neel Khare - 8 months ago

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@Neel Khare That's fine don't stress over it, it's just part of my school project:) Good luck with the exams bro.

Dan Ley - 8 months ago

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@Dan Ley Thanks But I will try

Neel Khare - 8 months ago

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No, \(d^2=a^2-b^2\), so \(d=\sqrt{a^2-b^2}\).

Dan Ley - 8 months ago

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Ok

Neel Khare - 8 months ago

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@Neel Khare don't worry about it, I just multiplied the equation out so that there were no fractions, and replaced \(\sin^2c\) with \(1-\cos^2c\). Then you can show that the two expressions are equal, but it's not fun or elegant or particularly difficult...

Dan Ley - 8 months ago

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Comment deleted 7 months ago

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I think the right person for this is @Neel Khare

Ayush Rai - 8 months, 1 week ago

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