\(15^{23}+19^{23} \equiv (-2)^{23}+2^{23} \equiv -1((-2)^3)-1((2^3)) \equiv 0 \pmod{17}\).
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Brilliant Member
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1 year, 2 months ago

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@Brilliant Member
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Thanks, for the beautiful answer. I was totally perplexed as it was not even solved with Euler's, Fermat, or Wilson's theorem. Now, I see the answer comes just from the basic properties of modular arithematic. Thanks a lottttt!
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Puneet Pinku
·
1 year, 2 months ago

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TopNewest\(15^{23}+19^{23} \equiv (-2)^{23}+2^{23} \equiv -1((-2)^3)-1((2^3)) \equiv 0 \pmod{17}\). – Brilliant Member · 1 year, 2 months ago

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– Puneet Pinku · 1 year, 2 months ago

Thanks, for the beautiful answer. I was totally perplexed as it was not even solved with Euler's, Fermat, or Wilson's theorem. Now, I see the answer comes just from the basic properties of modular arithematic. Thanks a lottttt!Log in to reply