Main post link -> https://brilliant.org/practice/algebra/basic-operations-1/exponents/3/

In this Problem he solved it by breaking the question into brackets !! but even then each bracket will equal zero and by summing or subtracting those brackets we get 0 !!! how could he come up with that 23!!

No vote yet

2 votes

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestNote that there is a minus sign before \((-1)^{a}\) for odd values of \(a\).

Log in to reply

The final answer is 26 (not 23 like you mentioned).

As pointed out, each of the terms contribute a value of 1 to the sum, and there are 26 terms.

Log in to reply