If all those little (let's call them fubbies) were allowed to stand wherever they wanted to, but only in one of the positions they're occupying right now, what would be the probability that they would get the wave perfect? Assume that all the fubbies have their own timing at which they'll put their hand up, unaffected by their position. Also assume that there are only \(7\) of them, and ignore the ones behind. They make it too hard.

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## Comments

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TopNewestGiven that \(H\) and \(W\) are real numbers and

\[\large{\theta=\pi\left(10^{\huge{\frac{\sin^{-1}\left(\log\left(\int_{0}^{\infty}x^{\left(W\cdot0 \cdot 0 \cdot H \cdot 0 \cdot 0\right)!}e^{-x}dx\right)\right)}{\cos\pi+i\sin\pi}+1}}\right)}\]

\[+1+2+3+4+6+7+8+9+10+11+12+13,\]

find the value of \(\tan\theta^{\circ}\).

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\( - \cot 1^{\circ}\)

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@Llewellyn Sterling

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Just...wow.

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If all those little (let's call them fubbies) were allowed to stand wherever they wanted to, but only in one of the positions they're occupying right now, what would be the probability that they would get the wave perfect? Assume that all the fubbies have their own timing at which they'll put their hand up, unaffected by their position. Also assume that there are only \(7\) of them, and ignore the ones behind. They make it too hard.

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Nice Job.

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Hard, eh? :P

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Only in the current position (as shown in gif) the wave is perfect? All other arrangements, its not?

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Yup.

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