Waste less time on Facebook — follow Brilliant.
×

Will anyone help me with this?

A function is given \(f(x)= 2x^{4} - 3x^{3} + 4x^{2} - 5x +6\), calculate the sum of \(S= A+B+C+D+E\) , if \(f(x)= A(x-1)^{4} + B(x-1)^{3} + C(x-1)^{2} + D(x-1) +E\)

Note by Sopheak Seng
3 years, 10 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Make the substitution x = z - 1 and expand f(x) to get 2z^5 + 5z^4 + 7z^2 + 2z + 4. Hence, S = 2 + 5 + 7 + 2 + 4 = 20.

Michael Mendrin - 3 years, 10 months ago

Log in to reply

Wouldn't we take \( x = z + 1 \). Because If \( x = z - 1 \), we'd have \( x + 1 = z \) and the f(x) you got would be \( 2(x+1)^5 \ldots \).

Siddhartha Srivastava - 3 years, 10 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...